整数反转

发表于

https://leetcode-cn.com/problems/reverse-integer/

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/**
     * @param {number} x
     * @return {number}
     */
    var reverse = function(x) {
        if(x>0){
            return reverseZ(x)
        }
        else{
            x=0-x;
            return 0-reverseZ(x)
        }
    };
    var reverseZ= function(x){
        if(x>=Math.pow(2,31)){
            return 0
        }
        let y=[],i=1;
        while(x>=1){        
         y.push((parseInt(x%10)))
         x/=10
        }
        let res=Number(y.join().replaceAll(",",""))
        if(res>Math.pow(2,31)) 
        return 0
        return res
    }